Precalculus Graph y=2 (x3)^25 y = −2(x − 3)2 5 y = 2 ( x 3) 2 5 Find the properties of the given parabola Tap for more steps Use the vertex form, y = a ( x − h) 2 k y = a ( x h) 2 k, to determine the values of a a, h h, and k k a = − 2 a = 2 h = 3 h = 3 k = 5 k = 5The tangent at the point P (x 1 , y 1 ) to the parabola y 2 = 4 a x meets the parabola y 2 = 4 a (x b) at Q and R, then the midpoint of Q R is View solution If the distances of two points P and Q which lie on a parabola y 2 = 4 a x from focus are 3 and 1 2 units respectively then distance of the point of intersection of tangents at P and QThe vertex form of a quadratic equation is y = n(x − h) 2 k, where (h, k) gives the coordinates of the vertex of the parabola in the xyplane and the sign of the constant n determines whether the parabola opens upward or downward If n is negative, the parabola opens downward and the vertex is the maximum The given equation has the values h = 3, k = a, and n = −1
Quadratic Function
